x^2+36x-5152=0

Solution for x^2+36x-5152=0 equation:

x^2+36x-5152=0

a = 1; b = 36; c = -5152;
Δ = b2-4ac
Δ = 362-4·1·(-5152)
Δ = 21904
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{21904}=148$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-148}{2*1}=\frac{-184}{2}
=-92
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+148}{2*1}=\frac{112}{2}
=56
$